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1058. A+B in Hogwarts (20)
阅读量:5065 次
发布时间:2019-06-12

本文共 1228 字,大约阅读时间需要 4 分钟。

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28
#include
#include
using namespace std;int main(){ int Galleon1,sickle1,knut1; int g_sum=0,s_sum=0,k_sum=0; scanf("%d.%d.%d %d.%d.%d",&Galleon1,&sickle1,&knut1,&g_sum,&s_sum,&k_sum); g_sum+=Galleon1; s_sum+=sickle1; k_sum+=knut1; int flag = k_sum/29; k_sum = k_sum%29; s_sum+=flag; flag=s_sum/17; s_sum=s_sum%17; g_sum+=flag; printf("%d.%d.%d\n",g_sum,s_sum,k_sum); return 0;}

  

转载于:https://www.cnblogs.com/grglym/p/7725203.html

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